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4x^2-39x+75=0
a = 4; b = -39; c = +75;
Δ = b2-4ac
Δ = -392-4·4·75
Δ = 321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-\sqrt{321}}{2*4}=\frac{39-\sqrt{321}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+\sqrt{321}}{2*4}=\frac{39+\sqrt{321}}{8} $
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